Adding vectors using trigonometric methods
A) Pythagoras's Theorem & Trigonometry
Review: Mathematical concepts in trigonometry
Recall Pythagoras's Theorem: C^{2} = A^{2 }+ B^{2 }
This theorem applies only to right angle triangles like the one below.
In other words, it can be used only when vector A is perpendicular to vector B
The three basic trigonometric identities that can be derived from a right angle triangle whose included angle is , are:
B) Sine and Cosine Laws Method
For triangles that are NOT rightangle triangles we can use modified trigonometric laws known as the cosine and sine laws:
The triangle below is a generalized isosceles triangle where none of the sides are perpendicular to one another.
Note that we use lower case letters to represent the sides of the triangle and upper case letters to represent the included angles.
Memorize these two laws ... they will come in very handy
 The sine Law
 The Cosine Law
Example: What was the total displacement of a balloon that drifts for 7 km in a [NE] direction and then is pushed by a wind in a southerly direction for another 3 km.
In case you forgot: [NE] is a direction half way between the y axis [N] and the x axis [E] > [N45^{0}E]
Use the sine/cosine laws to solve this problem.
Solution:
As usual we will start with a quick sketch
Knowing the rules of angles here is also important. For example the Opposite Angles Theorem tells us that the angle between d1 and d2 (angle B) is also 45^{0}  see diagram below:
Stepbystep ...

We first apply the cosine Law to find the magnitude of the resultant vector, d_{total}
where:
b = d_{total} (to be calculated)
a = 3 km [S];
c = 7 km [NE]
and
_{ B = 45}^{0}
therefore applying the cosine law
b^{2} = (3)^{2} + ( 7)^{2}  2(3)(7)(cos(45^{0}))
and b^{2} = 28.3
and [ by taking the square root of b^{2}]
b = 5.32 km > this is the magnitude of d_{total}
2. Finding the direction of the resultant  Apply the Sine Law to find the value of the angle
from the general equation
we can only use two of the terms for which we have information:
cross multiply, isolate, and solve for sin
sin = 0.398
Now use the inverse of sin (sin^{1}) to find the angle in degrees
= invsin(0.398) = 23.50^{0}
3. Make a final statement indicating your findings
the vector d_{total }has direction (45^{0} + 23.5^{0})  see diagram below
^{} d_{total}^{ }= 5.32 km [N68.5^{0}]